Do you know find the area of the rhombus?
Although a rhombus has
a structure similar to a square, there is a difference between a square and a
rhombus.
Although the four sides
of a rhombus are equal as to the four sides of a square, the diagonals of a
rhombus are not equal to as the diagonals of a square. This difference is what
differentiates a rhombus from a square.
Students are asked to
remember the shape of a diamond when they are asked to draw a model picture of
a rhombus to make it easier to remember.
Let us first look at
the shape of a rhombus in which all four sides are equal and the diagonals are
not equal.
This is the rhombus. We
must not forget that if its diagonals are equal, it becomes a square.
Don't forget that we
said that diagonals help us a lot when finding at area.
Now let's draw
diagonals to this rhombus. First let's draw the horizontal diagonal.
What do you think of
when you see this horizontal diagonal? Doesn't this diagonal divide the rhombus
into two triangles? You understand now?
That's right, if you
find the sum of the areas of these two triangles in the same way you found the
area of a quadrilateral, by now you will have found the formula for the area of a rhombus?
Does this horizontal
diagonal form a triangle above and a triangle below and is the base of both
triangles i.e. b?
Now all we need are the
heights of the triangles? For that we just need to draw the vertical diagonal
of the rhombus. How do you draw that? Like this, look at the picture.
Now you can see that
this vertical diagonal also sets the diagonal as a set of two triangles, left
and right.
Next you need to know a
mathematical fact about the diagonals of a rhombus.
Cut out the rhombus we
have drawn on the same paper and fold it along the horizontal diagonal. Now you
will understand a truth. It means that the vertical diagonal is bisected by the
horizontal diagonal. Similarly if we fold through the vertical diagonal we can
see that it bisects the horizontal diagonal. What is right?
And another fact that
can be seen here is that the upper and lower triangles are equal when folded
along the horizontal diagonal. Similarly, when folded along the vertical
diagonal, the right and left triangles are also seen to be equal.
Since we have drawn two
diagonals for the rhombus, let's denote the horizontal diagonal by the variable
d1 and the vertical diagonal by the variable d2 to distinguish
between the two.
When we look through
the horizontal diagonal we get a triangle at the top and a triangle at the
bottom, don't we? The sum of these two triangles is the area of the rhombus. Also,
aren't these two triangles equal? So if we find the area of any one triangle and
multiply it by two, we can get the area of the rhombus, right?
Do we just find the
area of the triangle above and multiply it by two?
The base b of the
triangle above is d1 we are concerned here? Also, the height h of
the triangle is half of the vertical diagonal we are concerned here? Since it's
the vertical diagonal of 900 and it's bisected by the horizontal
diagonal, isn't the height here d2/2?
You can also see this
in the image below.
So the area of the triangle is ½bh
square units so here ½d1×(d2/2) square units is correct?
Now since the area of the rhombus is 2 × the
area of the triangle,
Area of rhombus = 2 × ½d1×(d2/2)
square units. So if we multiply the 2 above by the 2 below d2, we
get ½d1d2 square units? It is the formula for the area of
a rhombus? What do you
understand?
Next we need to find
the formula for the area of a trapazium. Will we see it tomorrow?
*****
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